How to output all the odd and even numbers using a for loop?

How to output all the odd and even numbers using a for loop? If someone has already entered two integers.

How to output all the odd and even numbers using a for loop?
more info needed. what are the entered integers for?





as for odd and even numbers, if ( number [remainder operator] 2 = 0 ) then its even number, else its odd.
Reply:use 'mod' for VB


use '%' for C





example





5%2 = returns 1 (set this as ODD)


4%2 = returns 0 (set this as even)
Reply:Use modulos (aka do a mod 2)





Something like (pseudo-code)





intFirst = [user input]


intSecond = [user input]





for i in intfirst to intSecond:


if(i%2 == 0) then


print i+" is an even number"


else


print i+" is an odd number"


end if





in Ruby





intFirst = gets.strip.to_i #ask for input, strip whitespace, convert to integer


intSecond = gest.strip.to_i


#loop through the range and test mod 2


for i in intFirst...IntSecond do


if(i%2 == 0) then


puts i.to_s+" is an even number"


else


puts i.to_s+" is an odd number"


end #end of the if statement


end #end of the for loop
Reply:for x = all odd values in range low to high


print x


for x = all even values in range low to high


print x


Get the remainder of the result of value / 2


If it is 1, value is odd else it is even.





in 'C'


int odd(int x)


{


return (x % 2) ? x : x + 1; // returns an odd value


}


int even(int x)


{


return (x % 2) ? x + 1 : x; // returns an even value


}


int main()


{


int i, x, y;


... code to get two integers into x, y omitted.


for (i = odd(x); i %26lt; odd(y); i += 2)


printf("%d\n", i);


for (i = even(x); i %26lt; even(y); i += 2)


printf("%d\n", i);


return 0;


}



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