What is the resulting induced current if the loop has a resistance of 2.00 ?

A flat loop of wire consisting of a single turn of cross-sectional area 7.60 cm2 is perpendicular to a magnetic field that increases uniformly in magnitude from 0.500 T to 2.90 T in 1.01 s. What is the resulting induced current if the loop has a resistance of 2.00 ?

What is the resulting induced current if the loop has a resistance of 2.00 ?
You can use Faraday's law for this:





emf = IR = N * d(flux)/dt





because the Area remains the same, d(flux)/dt is equivalent to A*dB/dT, which can be rewritten as A* delta B / delta T





Thus, you have the equation:





IR = N*AB/t





where I = current, R = resistance, N = number of loops, A = area, B = change in magnetic field, and t = change in time





R = 2


N= 1 (there is only one loop)


A = 7.6 cm^2 = .00076 m^2


B = 2.4 T


t = 1.01 s





Your final answer: 9.03 * 10^-4 A
Reply:First find the voltage, which is simply the product of the flux change times the area, divided by the time. Using E = I R, the current will be numerically equal to half the voltage.



motorcycles